フィルターのクリア

how to create a series of changes over the loop variable and can assign a value to it

1 回表示 (過去 30 日間)
how to create a series of changes over the loop variable and can assign a value to it Example
for r=1:3
A|r| = r
B|r| = A|r+1| + A|r|
end
the result
A1=1
A2=2
A3=3
B1=3
B2=5
...

採用された回答

Youssef  Khmou
Youssef Khmou 2013 年 5 月 19 日
try :
n=1:30;
A=n;
for r=1:length(n)-1
B(r)=A(r+1)+A(r);
end
plot(A), hold on, plot(B)
  3 件のコメント
Youssef  Khmou
Youssef Khmou 2013 年 5 月 19 日
hi, In this case, the dimension grows inside the loop so you need to use the cell :
for i=1:4
A{i}=rand(3,4+i);
end
Pham Ngoc Thanh
Pham Ngoc Thanh 2013 年 5 月 19 日
Hi I have tried
for i=1:4
A{i}=rand(3,4+i);
end but have an error: "Cell contents assignment to a non-cell array object" What can I do?

サインインしてコメントする。

その他の回答 (2 件)

Image Analyst
Image Analyst 2013 年 5 月 19 日
You don't have a good condition for when r = the last value, for example, what is A(4) when r only goes to 3. But ignoring that last element, this will work for you:
n=10
A=1:n
B = A + [A(2:end) 0]
In command window:
n =
10
A =
1 2 3 4 5 6 7 8 9 10
B =
3 5 7 9 11 13 15 17 19 10
If you want to add the last element of A then turn the 0 into A(n).

Image Analyst
Image Analyst 2013 年 5 月 19 日
This works just fine (if that's what you want to do):
clc;
for i=1:4
A{i} = rand(3,4+i)
end
whos A
A =
[3x5 double]
A =
[3x5 double] [3x6 double]
A =
[3x5 double] [3x6 double] [3x7 double]
A =
[3x5 double] [3x6 double] [3x7 double] [3x8 double]
Name Size Bytes Class Attributes
A 1x4 1072 cell
See how it grows with each iteration and the size of the last-added cell is bigger each time? Just what you wanted, right?
  3 件のコメント
Image Analyst
Image Analyst 2013 年 5 月 22 日
You can't multiply a 3x5 by a 6x3 - it doesn't work. Anyway, I see you've already accepted another answer so I guess you got it solved that way.
Pham Ngoc Thanh
Pham Ngoc Thanh 2013 年 5 月 22 日
I'm sorry. B{i} = A{i}'*{A{i+1} [5x3]*[3x6}
Now i can understand some things. Thanks you a lot.

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeCreating and Concatenating Matrices についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by