Hi there. I have the following example of code:
mydata_x = random_data % isn't important how data i have
mydata_y = random_data
a = 10;
b = 0.5;
c = 3;
To calculate the fit of mydata I use to calculate d:
[fit1,gof1] = fit(mydata_x,mydata_y,'(10-0.5.*x.*d)/(3+0.5.*x.*d)');
There is a way to substitute 10,0.5 and 3 with the equivalent vaiables: a,b and c; like the following code:
[fit1,gof1] = fit(mydata_x,mydata_y,'(a-b.*x.*d)/(c+b.*x.*d)');

 採用された回答

Steven Lord
Steven Lord 2021 年 3 月 1 日

1 投票

See the "Create Fit Options and Fit Type Before Fitting" example on the documentation page for the fit function. It uses the 'problem' option to specify that certain variables in the expression to be fitted are problem parameters that will be specified when the expression is fitted, not coefficients whose values should be determined by the fitting process.

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