Why does symbolic integration return the wrong answer for this integral?

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Gareth Fuller
Gareth Fuller 2021 年 2 月 23 日
コメント済み: Walter Roberson 2021 年 2 月 23 日
Hello! I'm trying to integrate 1/(1-x)^2 with the bounds 0 to x.
Now, other sources (Like WolframAlpha) return the result as -x/(x-1). However, MATLAB returns inf.
Can anyone explain why this would be?
syms x
expr = 1/(1-x)^2
int(expr, 0, x)
ans =
Inf

採用された回答

Walter Roberson
Walter Roberson 2021 年 2 月 23 日
syms x a
expr = 1/(1-x)^2
expr = 
F = int(expr, x, 0, a)
F = 
subs(F,a,x)
ans = 
  2 件のコメント
Gareth Fuller
Gareth Fuller 2021 年 2 月 23 日
That works- All I've got to do to get the desired result is some shuffling around of terms.
I'm curious as to why the Subs step is needed, and why it can't get the piecewise function with int(expr,0,x).
Thanks for providing a solution- that certainly helped me out.
Have a wonderful day!
Walter Roberson
Walter Roberson 2021 年 2 月 23 日
I am not sure. My expectation was that I would be able to control the output by adding in an assume() or tossing in an 'IgnoreAnalyticConstraints' option, but those did not work.

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