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Theory of Bicubic interpolation

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Shubha B.
Shubha B. 2021 年 2 月 23 日
コメント済み: Shubha B. 2021 年 2 月 25 日
For the bicubic code which is given in the this link https://www.mathworks.com/matlabcentral/answers/405846-bicubic-interpolation-direct-interpolation-formula-matlab-source-code, where can I get the expalnation of this code. The explanation which is given in the link https://en.wikipedia.org/wiki/Bicubic_interpolation
is not matching.

回答 (1 件)

Bruno Luong
Bruno Luong 2021 年 2 月 24 日
編集済み: Bruno Luong 2021 年 2 月 24 日
It has been answered here
In 2D you do in one direction followedred by another.
%%
x = [-1:2];
y = [-1:2];
[X,Y] = meshgrid(x,y);
xq = rand;
yq = rand;
Z = rand(size(X));
Zq = interp2(x,y,Z,xq,yq,'bicubic')
% Check bicubic formula
Pl = [1.5,-2.5,0,1];
Pr = [-0.5,2.5,-4,2];
cubicp = @(x) (x<=1).*polyval(Pl,x) + (x>1 & x<2).*polyval(Pr,x);
cubic = @(x) cubicp(abs(x));
Zq = 0;
[~,i0] = histc(xq,x);
[~,j0] = histc(yq,y);
for i = i0-1:i0+2
for j = j0-1:j0+2
k = sub2ind(size(Z),j,i);
Zq = Zq + cubic(X(k)-xq)*cubic(Y(k)-yq)*Z(k);
end
end
Zq
  3 件のコメント
Bruno Luong
Bruno Luong 2021 年 2 月 25 日
編集済み: Bruno Luong 2021 年 2 月 25 日
The theory is in the Key's paper on the reference of the document of interp1 and interp2 and in the link II provide (coeffcient in eqt 4 do you read it?).
Apparently it's free access here
Mostly coefficients are computed to provide a smooth convolution kernel and compact support.
The example I give is formula for interpolation at a singe point (xq,yq).
For more points just loop on it. No relevant if you want to understand the formula.
Shubha B.
Shubha B. 2021 年 2 月 25 日
thank you sir.

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