i've a matrix of 6x4 and i want to count the rows how many times it occur in a matrix

3 ビュー (過去 30 日間)
Raman
Raman 2013 年 5 月 8 日
編集済み: Jan 2017 年 8 月 9 日
let say the matrix is
A=[ 12 45 67 89
34 56 78 65
12 45 67 89
53 55 21 90
12 45 67 89
53 55 21 90 ]
i want the output to be as:
12 45 67 89 ----- 3 % because it occurs 3 times
34 56 78 65 ------1
53 55 21 90 ------2
plz help me

採用された回答

Azzi Abdelmalek
Azzi Abdelmalek 2013 年 5 月 8 日
A=[ 12 45 67 89
34 56 78 65
12 45 67 89
53 55 21 90
12 45 67 89
53 55 21 90 ]
[a,b,c]=unique(A,'rows','stable');
v=arrayfun(@(x) sum(c==x),1:size(a,1))';
out=[a v]
  2 件のコメント
Emma Cairns
Emma Cairns 2017 年 8 月 9 日
I have an instance where I need to do this twice with two separate matrices and I keep getting the same output for both using this code, is there any way I can make it work? Thanks!
Jan
Jan 2017 年 8 月 9 日
編集済み: Jan 2017 年 8 月 9 日
@Emma: Yes, there is a way. Of course there is. If you post the relevant part of your code (preferably as a new question and not by high-jacking this thread), we can even suggest a solution.
Andrei's method is slightly faster and (c)leaner.

サインインしてコメントする。

その他の回答 (1 件)

Andrei Bobrov
Andrei Bobrov 2013 年 5 月 8 日
A=[ 12 45 67 89
34 56 78 65
12 45 67 89
53 55 21 90
12 45 67 89
53 55 21 90 ];
[a,c,c] = unique(A,'rows');
out = [a, histc(c,1:max(c))];

カテゴリ

Help Center および File ExchangeCreating and Concatenating Matrices についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by