differentiation of time series data
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I have a time series data 'X 'of size 20000 X 50. My step size dt= 0.05
how do I find the velocity of these data
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Walter Roberson
2021 年 2 月 15 日
If ts is the timeseries() variable then
X = ts.Data;
extracts the data.
With your data being 20000 x 50 my guess is that you have 20000 measurements for each of 50 entities, rather than 50 measurements for each of 20000 entities. If I am correct, then you would want the y gradient:
xstep = 1; %doesn't really matter, we are going to ignore
tstep = 0.5; %does matter
[~, ygrad] = gradient(X, xstep, tstep); %horizontal step first, vertical step second
18 件のコメント
Walter Roberson
2021 年 2 月 21 日
xstep = 1; %doesn't really matter, we are going to ignore
tstep = 0.5; %does matter
Xunwrapped = unwrap(X, [], 2);
[~, velocity_gradient] = gradient(Xunwrapped, xstep, tstep); %horizontal step first, vertical step second
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