How to calculate sum without loop?

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Numerical Noob 2021 年 2 月 12 日

コメント済み: Numerical Noob 2021 年 2 月 12 日

Hello,

I must calculate S in the range of n=1 to n=100 without a loop.

s=(1...100)(101-n)*cos(n/100)

Example= 100*cos(1/100) + 99*cos(2/100) ... + 1*cos(100/100)

KSSV 2021 年 2 月 12 日

n = 1:100 ;
s = sum(n.*cos(n/100))

Aditya Kommajosula 2021 年 2 月 12 日

編集済み: Aditya Kommajosula 2021 年 2 月 12 日

If I understand the OP's question right, the solution might have to be:

n = 1:100;
s = sum(n(end:-1:1).*cos(n/100));

Regards

Numerical Noob 2021 年 2 月 12 日

Thank you Aditya, I tried it with an iterative approach with n=1..3. Your solution is right.

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