index exceed matrix dimensions

Hi, every body

why I have an index exceed matrix dimesnions in this code, pls help

z1=linspace(0,D,1000); 
z2=linspace(0,D1,1000); 
z3=linspace(0,D2,1000); 
z=[z1,z2,z3];
Dv=[D,D1,D2];
for j =1:3
p1i=(4*mu*N*I)/(pi*L);
p2i=1./((((z(j)./(L./2)).^2)+1).*sqrt(((z(j)./(L./2)).^2)+2));
p3i=1./(((((z(j)-D(j))./(L./2)).^2)+1).*sqrt((((z(j)-D(j))./(L./2)).^2)+2));
Bi=(p1i*(p2i+p3i))*10000;
end

Answer 1

[KALYAN ACHARJYA]

Issue with this line

p3i=1./(((((z(j)-D(j))./(L./2)).^2)+1).*sqrt((((z(j)-D(j))./(L./2)).^2)+2));

You are trying to access D as a vector, is that so?

Also you used D in the following line also

z1=linspace(0,D,1000); 

D might be scalar data (one numeric value), as per z1 statement

More: It may be typo mistake, D may be Dv, bacause you have defined Dv, but not use anywhere in the code.

[Oday Shahadh]

Oh my God , I did not noticed this, but why I got just three values while it must be result a set of data as the same length of z

z1=linspace(0,D,1000);

z2=linspace(0,D1,1000);

z3=linspace(0,D2,1000);

z=[z1,z2,z3];

Dv=[D,D1,D2];

Bii=[];

for j =1:3

p1i=(4*mu*N*I)/(pi*L);

p2i=1./((((z(j)./(L./2)).^2)+1).*sqrt(((z(j)./(L./2)).^2)+2));

p3i=1./(((((z(j)-Dv(j))./(L./2)).^2)+1).*sqrt((((z(j)-Dv(j))./(L./2)).^2)+2));

Bi=(p1i*(p2i+p3i))*10000;

Bii=[Bi Bii];

end

[KALYAN ACHARJYA]

See the for loop j, 1 to 3 only. Note Dv having length 3 only