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Question on 2D projective transformation

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Michael
Michael 2021 年 2 月 5 日
コメント済み: Michael 2021 年 9 月 21 日
The help page on Matrix Representation of geometric tranformations, under 2D projective transformations states that in the transformation matrix
[1 0 E; 0 1 F; 0 0 1]
That E and F influence the vanishing point. These seem to emulate rotating the image around the x or y axis if this were a 3D object being rotated. So if I take an image of a dot grid, e.g.
And I perform the following
t = [1 0 .002; 0 1 0; 0 0 1]
tform = projective2d(t);
outImg = imwarp(im,tform);
I get this image as a result
So if my x axis were left/right and y axis up/down this seems to rotate around the y axis. I would like to control the angle of rotation, what exactly does .002 represent here? What I'd like to do is simulate rotating this image, say 3 degrees around the y axis.
  2 件のコメント
Meriem Chetmi
Meriem Chetmi 2021 年 9 月 21 日
Hello,
did you maybe find the relation between the rotation angles and these E , F parameters? I'm facing the same problem
Thank you
Michael
Michael 2021 年 9 月 21 日
Hi, I did not look into this any further. My goal was to create images while simulating rotation around the x,y,z axis. I ended up doing this with the OpenCV function WarpPerspective.

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