Please help with the trig integral

I'm trying to take the integral of the following function.

arctan[sin(phi)/sqrt{(sin(x)^2-sin(phi)^2}]*sinx*dx

The interval is (degree10, degree15)

phi=9.4 degree

Here is what I have

fi=9.4*pi/180;

theta1=10*pi/180;

theta2=15*pi/180;

fun1=@(x)sqrt((sin(x)).^2-(sin(fi)).^2);

fun2=@(x)atan(sin(fi)./fun1).*sin(x);

q=integral(fun2,theta1,theta2);

Thank you very much!

Answer 1

[Mike Hosea]

On the line defining fun2, change "fun1" to "fun1(x)".