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Findgroups, order of unique values in an array

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ardeshir moinian
ardeshir moinian 2021 年 2 月 3 日
コメント済み: Stephen23 2021 年 2 月 4 日
Hi,
I am trying to use "findgroups" in order to later split my data into different groups. But the order at which the groups are seperated is important for me. Using "findgroups" the order of groups is not "stable". How can I change that?
I did this:
[G ID]=findgroups(labels_all);
But
ID
doesn't come in that same order as
labels_all
I know that in unique, stable can fix this
q=unique((labels_all),'stable')
here q will be in order that unique values occur in labels_all.
Thank you!

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Stephen23
Stephen23 2021 年 2 月 3 日
[ID,~,G] = unique(labels_all,'stable')
  2 件のコメント
ardeshir moinian
ardeshir moinian 2021 年 2 月 4 日
Hi Stephen,
Thank you for your answer, and do you know if I use these unique groups in
mean_data=splitapply(@mean,data,G);
would the mean_data stay in the same order as the groups that I found using unique(...,'stable') or not?
Thank you!
Stephen23
Stephen23 2021 年 2 月 4 日
Lets try it:
G = [2,3,1,2,1,3];
D = [4,5,0,0,2,1];
splitapply(@mean,D,G)
ans = 1×3
1 2 3
Yes, splitapply returns its outputs in the order given by the values of G.

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