Plotting multiple points on a graph using for loop

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Batrisyia Mohamad Asri
Batrisyia Mohamad Asri 2021 年 2 月 2 日
コメント済み: SHIVAM KUMAR 2021 年 2 月 5 日
Hi. I would like to plot multiple points on a graph using for loop and subplot. I have an xi value of 0.2 to 0.8 with increments of 0.2. And the for loop is used to go through each xi value. The legend can be hardcoded and is positioned in the 'best' location. The result should look like the first subplot below.
The equation is given by the pic below
This is what i've done so far.
clc;clear all;close all
y = @(t,xi,omega) 1-exp^-xi*omega*t/sqrt(1-xi^2)*sin(omega*sqrt(1-xi^2)*t+acos(xi));
omega = 10.26;
t = linspace(0,1,200);
%plotting
xi= 0.2:0.2:0.8;
n = length(xi);
for i=1:n
subplot(2,1,1)
plot(xi,y)
end
Your help is very much appreciated! Thank you.

採用された回答

SHIVAM KUMAR
SHIVAM KUMAR 2021 年 2 月 2 日
編集済み: SHIVAM KUMAR 2021 年 2 月 4 日
Final version
clc
clear all
close all
fn= @(xi,omega,t) (1-((exp(-xi*omega*t))/sqrt(1-xi^2)).*sin(omega*sqrt(1-xi^2)*t+acos(xi)));
omega = 10.26;
t = linspace(0,1,200);
%plotting
x1= 0.2:0.2:0.8;
n = length(x1);
figure;
subplot 211
for i=1:n
Y = fn(x1(i),omega,t);
plot(t,Y)
hold on
end
legend("xi=0.2","xi=0.4","xi=0.6","xi=0.8")
ylim([0 2])
hold off
title("Omega=10.26")
xlabel("t")
ylabel("y")
%for second plot
next= fn(0.65,omega,t);
subplot 212
plot(t,next)
ylim([0 1.2])
hold on
legend("step response")
The indexes were not nicely choosen in function. I corrected that now though.
  9 件のコメント
Batrisyia Mohamad Asri
Batrisyia Mohamad Asri 2021 年 2 月 5 日
Got it! Thank you so much!
SHIVAM KUMAR
SHIVAM KUMAR 2021 年 2 月 5 日
Accept my answer if that is correct.

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