fimplicit3: colormapping (3DContourPlot)
4 ビュー (過去 30 日間)
古いコメントを表示
This is totally optional and off pure interest:
If I plot a manifold with this powerful function:
f = @(x,y,z) x.^2 + y.^2 - z.^2;
fimplicit3(f)
The shape is exactly as I want. Just if: how do I change colorgradient?
I'm not well versed with terms like Edgecolor etc.
0 件のコメント
採用された回答
Scott Ronquist
2021 年 1 月 30 日
Hi Niklas,
The color gradient in this figure can be changed by using the colormap function. Predefined colormaps are listed here, but any custom color map can be used by inputting a m x 3 numeric matrix into colormap. See example below:
>> f = @(x,y,z) x.^2 + y.^2 - z.^2;
>> fimplicit3(f)
>> colormap("cool")
Hope this helps!
0 件のコメント
その他の回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Colormaps についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!