Sort a matrix based on one row?
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lets say we have a 3x3 matrix as
a= 2 5 3;
2 8 1;
4 1 9;
and I want this matrix sorted based on its 2nd row in ascending order i.e.
answer= 3 2 5;
1 2 8;
9 4 1;
Thank you for any help you can offer.
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回答 (1 件)
Walter Roberson
2013 年 4 月 22 日
[temp, order] = sort(a(2,:));
answer = a(:,order);
3 件のコメント
Stephen23
2025 年 6 月 22 日
answer = sortrows(a.', 2).';
Using transpose, rather than complex conjugate transpose.
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