Legend Problem in Scatter Plotting

11 ビュー (過去 30 日間)
Ritesh Chandra Tewari
Ritesh Chandra Tewari 2021 年 1 月 27 日
コメント済み: Star Strider 2021 年 1 月 27 日
[m,n] = size(y);
x1 = X(:,1);
x2 = X(:,2);
for j=1:1:n
for i=1:1:m
if y(i,j)==1
scatter(x1(i,j), x2(i,j), 20, y(i,j),'k', '+');
else
scatter(x1(i,j), x2(i,j), 10, y(i,j),'y', 'filled');
hold on;
end
end
end
legend("Admitted","Not Admitted");
X is a 300x2 matrix consisting random data and y is a 300x1 matrix consisting only 0 and 1. I want to plot a 2D scatter graph of x1 and x2. Based on the value of y i.e. 0 or 1 the marker of the plot will be changed. But both the legend showing the same marker. I dont want to use any other plotting function , rather want to stick to scatter. The plot is showing like:

採用された回答

Star Strider
Star Strider 2021 年 1 月 27 日
See if this does what you want:
[m,n] = size(y);
x1 = X(:,1);
x2 = X(:,2);
for j=1:1:n
for i=1:1:m
if y(i,j)==1
hs1 = scatter(x1(i,j), x2(i,j), 20, y(i,j),'k', '+');
else
hs2 = scatter(x1(i,j), x2(i,j), 10, y(i,j),'y', 'filled');
hold on;
end
end
end
legend([hs1(1),hs2(1)],"Admitted","Not Admitted");
I obviously cannot test this with your data, so I am posting it as UNTESTED CODE.
.
  2 件のコメント
Ritesh Chandra Tewari
Ritesh Chandra Tewari 2021 年 1 月 27 日
Thanks buddy!
Star Strider
Star Strider 2021 年 1 月 27 日
As always, my pleasure!

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeDiscrete Data Plots についてさらに検索

製品


リリース

R2018a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by