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How to plot node numbers using matrix of nodes's coordinates?

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Vitaly
Vitaly 2013 年 4 月 18 日
回答済み: kyaw zaw 2017 年 7 月 8 日
Hi, my script plots a mesh grid using:
gplot(adj,NC,'-o')
where 'adj' is the adjacency matrix and 'NC' is the matrix of nodes' coordinates. It works absolutely fine, except for the fact that it doesn't plot the nodes' numbers on the graph.
For example, for a grid like this:
3-6-9
| | |
2-5-8
| | |
1-4-7
I need nodes' numbers to be on the graph and the nodes coordinates matrix is given by:
NC =
0 0
0 h
0 H1
w 0
w h
w H1
W1 0
W1 h
W1 H1
Where h's and w's are user's inputs.
The script also provides the matrix of nodes numbers, which for this example looks like this:
A =
1 4 7
2 5 8
3 6 9
I believe it is possible to use the above matrices to plot the nodes' numbers, but I don't know how. Any ideas?
  2 件のコメント
Marcos Rezk
Marcos Rezk 2016 年 5 月 13 日
how do you get the adjacency matrix

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採用された回答

Jonathan Epperl
Jonathan Epperl 2013 年 4 月 19 日
And text() doesn't give you the results you'd like? E.g.
k = 1:30;
[B,XY] = bucky;
gplot(B(k,k),XY(k,:),'-o')
axis square
for i=k
text(XY(i,1),XY(i,2),num2str(i,'%d'))
end
If that's not good enough, we could certainly do some cosmetics on it...
  1 件のコメント
Vitaly
Vitaly 2013 年 4 月 19 日
That's perfect, thanks. I've modified it a little bit and got what I wanted.

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その他の回答 (2 件)

kyaw zaw
kyaw zaw 2017 年 7 月 8 日
Can We set locations of Nodes by coordination method? For example, Node1 is at x=3, y=4 of each axis. Please see following figure!In figure, all Nodes are located at wherever they want. We want to locate those Nodes systematically. Please answer is it possible or not!

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