'inline' command at 'for' loop... can we?

can we put 'inline' command at 'for' loop
I want to save several inline function at an array... Available?

 採用された回答

Friedrich
Friedrich 2013 年 4 月 17 日
編集済み: Friedrich 2013 年 4 月 17 日

1 投票

Hi,
yes it should be possible but its better to create some Anonymous Functions instead of using inline, e.g.
f = cell(10,1);
for i=1:10
f{i} = @(x) x*i;
end
The output of f looks a bit strange because it seems to be the same function handle all the time, but it isn't:
>> f{1}(1)
ans =
1
>> f{2}(1)
ans =
2
>> f{3}(1)
ans =
3
>> f{3}(4)
ans =
12
Or:
f = cell(2,1);
for i=1:2
tmp = inputdlg('enter function handle')
f{i} = eval(tmp{:})
end
And enter things like:
@(x)x^2
@(x)x-3
Make the call to eval fail proof!!

1 件のコメント

Daniel Shub
Daniel Shub 2013 年 4 月 19 日
There is no need to hit it with the evil eval hammer, str2func seem perfectly designed for this purpose with hopefully a lot less side effects

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その他の回答 (2 件)

Masoud Ghanbari
Masoud Ghanbari 2013 年 4 月 17 日

0 投票

Hi
Actually I want to get the function from user and save it
not to be defined as f{i} = @(x) x*i;

12 件のコメント

Jan
Jan 2013 年 4 月 17 日
Please do not post details of the question as an answer, but inster it in the question, where readers expect them.
What does "get the function from user" exactly mean? It is impossible to guess this reliably.
Friedrich
Friedrich 2013 年 4 月 17 日
編集済み: Friedrich 2013 年 4 月 17 日
I think what he wants to do is the same as discussed here:
Still dont use inline, use eval to generate the function handle. See me updated first post.
Masoud Ghanbari
Masoud Ghanbari 2013 年 4 月 18 日
Thanks Dear Friedrich
and what if i want to get the function from user by 2 variables like
f(i) = @(x,y) x+y
Friedrich
Friedrich 2013 年 4 月 18 日
As long the user enters a valid matlab expression you are fine to eval it.
>> user_input = '@(x,y) x+y'
user_input =
@(x,y) x+y
>> my_fcn = eval(user_input)
my_fcn =
@(x,y)x+y
>> my_fcn(3,10)
ans =
13
>>
Masoud Ghanbari
Masoud Ghanbari 2013 年 4 月 18 日
Why we got error while changing 'inputdlg' to 'input' below ???
f = cell(2,1);
for i=1:2
tmp = inputdlg('enter function handle')
f{i} = eval(tmp{:})
end
And why error when user inputs '@(x,y)x+y' at inputdlg
number=input(' How Many Conditions Do You Have ? ');
f = cell(number,1);
for i=1:number
user_input = inputdlg('Enter The function :');
f{i} = eval(user_input);
end
Friedrich
Friedrich 2013 年 4 月 19 日
input returns a character array wheras inputdialog gives back a cell.
This @(x,y)x+y should give any error. What error do you get?
Masoud Ghanbari
Masoud Ghanbari 2013 年 4 月 19 日
When I Run
number=input(' How Many Conditions Do You Have ? ');
f = cell(number,1);
for i=1:number
user_input = inputdlg('Enter The function :');
f{i} = eval(user_input);
end
inputdlg appear and when i enter
@(x,y)x+y
i will face error at this line below
f{i} = eval(user_input);
Iman Ansari
Iman Ansari 2013 年 4 月 19 日
編集済み: Iman Ansari 2013 年 4 月 19 日
Hi. Use this:
f{i} = eval(user_input{1});
Masoud Ghanbari
Masoud Ghanbari 2013 年 4 月 19 日
Hi Iman
It Does not work...
Friedrich
Friedrich 2013 年 4 月 19 日
Dude ;) Post your intput and the error message. A simply does not work wont help.
Masoud Ghanbari
Masoud Ghanbari 2013 年 4 月 20 日
Ok Dear Friedrich ... Please Just Do What Ever You Know... I'm Really Stucked At This
See Here:
https://www.youtube.com/watch?v=zQiAgVLXknI
Friedrich
Friedrich 2013 年 4 月 22 日
You need to zuse {} instead of () when you call eval. inputdlg gives back a cell. Also don't use i to index into it. This should work:
f{i} = eval(user_input{1})

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Masoud Ghanbari
Masoud Ghanbari 2013 年 4 月 20 日

0 投票

Ok Dear Friedrich ... Please Just Do What Ever You Know... I'm Really Stucked At This
See Here:
https://www.youtube.com/watch?v=zQiAgVLXknI

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