2D Interpolation with different sized matrices
15 ビュー (過去 30 日間)
古いコメントを表示
x = [1 2 3 4 5];
y = [1 2 3 4 5];
z = [1 2 1 2 3; 3 4 3 4 5; 5 6 5 6 7; 3 4 3 4 5; 1 2 1 2 3];
]
Hello,
Is there a method to obtain the corresponding x value when the y and z values are provided? I tried interp2 which gives the value of z when x and y are given. The command does not offer me the expected option. Can somebody guide me to solve my problem?
Thanks in advance.
1 件のコメント
回答 (1 件)
Jan
2021 年 1 月 18 日
A bold guess of what "corresponding x value when the y and z values are provided" means:
x = [1 2 3 4 5];
y = [1 2 3 4 5];
z = [1 2 1 2 3; 3 4 3 4 5; 5 6 5 6 7; 3 4 3 4 5; 1 2 1 2 3];
yWant = 2;
zWant = 3;
match = (y == yWant) & (z == zWant); % Auto-expand, Matlab >= R2016b
xResult = x(any(match, 1));
3 件のコメント
Jan
2021 年 1 月 19 日
My code does only find exact matchs, so it is not an interpolation. Therefore I asked for examples of inputs and the wanted outputs. Please answer this question for clarification, because it is required to understand, what you want to get. I cannot guess, what you want as output for the inputs y=2.5 and z=4.5 .
参考
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!