How can I apply circular shift on bits in MATLAB?
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I want to apply shift right operation on aset of bits
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Youssef Khmou
2013 年 4 月 12 日
hi,
suppose you have a vector a=011000011, then shift circularly the vector :
b=circshift(a,[1 1]), % if 1 is >0 then the vector is shifted the right
b=circshift(a,[1 -1])
b=circshift(a,[1 2]),
...
その他の回答 (1 件)
Walter Roberson
2013 年 4 月 11 日
MATLAB does not offer that operation directly.
You can extract the bits that would be shifted "off the bottom", do the shift, and then put the bits back on top. Or you can proceed numerically, such as
mod(x,2)*2^7 + floor(x/2)
7 件のコメント
Walter Roberson
2017 年 6 月 6 日
Do you want the individual bits to be left shifted, or do you want the elements to be left shifted relative to the other elements? For example if you had A = uint8([1 2 3 129]) to be circular left shifted by 2, then do you want the result B = uint8([3 129 1 2]) or do you want the result B = uint8([4, 8, 12, 6]) ?
If you want the elements to be left shifted relative to each other, then
B = circshift(A, -K, 2);
If you want the bits to be circular shifted, then use the code I posted above (which I made a couple of corrections to a moment ago.)
If you want the bits to be circular shifted and you want the operation to be expressed mathematically, it is possible. In the above code, replace
shifted_uMatrix = bitshift(uMatrix, K, uc) + bitshift( uMatrix, K-wl, uc);
with
shifted_uMatrix = mod(uMatrix, 2^(wl-K)) * 2^K + uMatrix ./ 2^(wl-K);
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