How does the code work?

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Faris Sulam
Faris Sulam 2021 年 1 月 9 日
コメント済み: Faris Sulam 2021 年 1 月 9 日
Hi guys, I am learning on how to use MATLAB and currently im learning about making a user defined function for the Simpson's rule. The following is the code that I am looking at from the textbook "Numerical Methods for Engineers and Scientists":
function [ s ] = test( FunName,a,b)
N=2;
h=(b-a)/N;
x=a:h:b;
y=FunName(x);
MaxTol=1.0;
I1=h/3*(y(1)+4*sum(y(2:2:N))+2*sum(y(3:2:(N-1)))+y(N+1));
N=2*N;
check=0;
while check==0;
h=(b-a)/N;
x=a:h:b;
y=FunName(x);
I2=h/3*(y(1)+4*sum(y(2:2:N))+2*sum(y(3:2:(N-1)))+y(N+1));
CurTol=abs(I1-I2)/I1*100;
if CurTol>MaxTol
check=0;
N=N*2;
I1=I2;
elseif CurTol<=MaxTol
check=1;
I1=I2;
end
end
disp(I1)
end
Now i just want to ask on what 'check' does in this code? Presumably that 'check' here tells MATLAB to continually iterate but I dont understand how it stops it. Thanks in advance
  4 件のコメント
David Hill
David Hill 2021 年 1 月 9 日
yes
Faris Sulam
Faris Sulam 2021 年 1 月 9 日
Thanks

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