for orders = [0:1:y]
disp(' ')
str3 = 'The coefficient of x^';
str4 = ' is ';
alltogether = [str3 num2str(orders) str4];
input(alltogether);
end
Part of the code im writing performs the above task, where y is variable depending previously what a user inputs. After the user has completed this section i would like all the numbers to be collated into a single vector form, like so;
The polynomial of interest has order 3.
The coefficient of x^0 is 1
The coefficient of x^1 is 2
The coefficient of x^2 is 3
The coefficient of x^3 is 4
P = [1 2 3 4]
Please and thanks

 採用された回答

Walter Roberson
Walter Roberson 2013 年 4 月 7 日

0 投票

Before the loop:
count = 0;
In the loop,
count = count + 1;
P(count) = input(alltogether);

2 件のコメント

Jessica Parry
Jessica Parry 2013 年 4 月 7 日
I cant seem to get this to work!
Walter Roberson
Walter Roberson 2013 年 4 月 7 日
count = 0;
for orders = [0:1:y]
disp(' ')
str3 = 'The coefficient of x^';
str4 = ' is ';
alltogether = [str3 num2str(orders) str4];
count = count + 1;
P(count) = input(alltogether);
end

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