フィルターのクリア

A complex number in the course of Müller's method

5 ビュー (過去 30 日間)
Ali Kiral
Ali Kiral 2020 年 12 月 31 日
コメント済み: Ali Kiral 2020 年 12 月 31 日
Consider the script below. I am trying to find the roots of by using Müller's method with initial estimations
N=input('Enter the degree of the main polynomial ');
C=input('Enter the constant ');
for k=1:N
a(k)=input('Enter a coefficient ');
end
a=[C,a];
Pol1=flip(a);
u=input('Enter the first estimate ');
v=input('Enter the second estimate ');
w=input('Enter the third estimate ');
z=input('Enter number of iterations ');
for n=1:z
delta0=(polyval(Pol1, v)-polyval(Pol1, u))/(v-u);
delta1=(polyval(Pol1, w)-polyval(Pol1, v))/(w-v);
h0=v-u;
h1=w-v;
a=(delta1-delta0)/(h1+h0);
b=a*h1+delta1;
c=polyval(Pol1,w);
g1=-2*c/(b+sqrt(b^2-4*a*c));
g2=-2*c/(b-sqrt(b^2-4*a*c));
if b+sqrt(b^2-4*a*c)>b-sqrt(b^2-4*a*c)
d=g1;
end
if b+sqrt(b^2-4*a*c)<b-sqrt(b^2-4*a*c)
d=g2;
end
x(n)=w+d;
u=v;
v=w;
w=x(n);
end
When I run it, MATLAB returns 'Undefined function or variable 'd'. d is calculated to be a complex number. MATLAB returns d when I run or separately, but does not do for the code. Why is that so?

採用された回答

Walter Roberson
Walter Roberson 2020 年 12 月 31 日
if b+sqrt(b^2-4*a*c)>b-sqrt(b^2-4*a*c)
d=g1;
end
if b+sqrt(b^2-4*a*c)<b-sqrt(b^2-4*a*c)
d=g2;
end
That code will not assign d under a few circumstances:
  • b+sqrt(b^2-4*a*c) == b-sqrt(b^2-4*a*c) -- which would occur if sqrt(b^2-4*a*c) == 0
  • one of the values is nan
  • sqrt(b^2-4*a*c) is imaginary but b is real; in that case, the > operator would compare only the real parts, and the real parts would be equal
Note:
b+sqrt(b^2-4*a*c)<b-sqrt(b^2-4*a*c) implies b + sqrt(b^2-4*a*c) - b < b - sqrt(b^2-4*a*c) - b implies sqrt(b^2-4*a*c) < - sqrt(b^2-4*a*c) implies 2*sqrt(b^2-4*a*c) < 0 implies sqrt(b^2-4*a*c) < 0 . However, algebraically, sqrt() is defined as "principle square root", which is positive when the value is positive, and is 1i * sqrt(-(b^2-4*a*c)) when b^2-4*a*c < 0 -- so sqrt(b^2-4*a*c) < 0 cannot happen unless you define an ordering of imaginary values with respect to 0. The MATLAB < operator ignores the imaginary component... but then you would be comparing 0 to 0, which would not be < .
Which is to say that your second test can never succeed, and your first test is always true unless b^2-4*a*c == 0 (a ligitimate test) or b^2-4*a*c < 0 (because the imaginary component is ignored)
  1 件のコメント
Ali Kiral
Ali Kiral 2020 年 12 月 31 日
A thorough explanation. Thank you, Walter

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeBiological and Health Sciences についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by