- b+sqrt(b^2-4*a*c) == b-sqrt(b^2-4*a*c) -- which would occur if sqrt(b^2-4*a*c) == 0
- one of the values is nan
- sqrt(b^2-4*a*c) is imaginary but b is real; in that case, the > operator would compare only the real parts, and the real parts would be equal
A complex number in the course of Müller's method
4 ビュー (過去 30 日間)
古いコメントを表示
Consider the script below. I am trying to find the roots of
by using Müller's method with initial estimations
N=input('Enter the degree of the main polynomial ');
C=input('Enter the constant ');
for k=1:N
a(k)=input('Enter a coefficient ');
end
a=[C,a];
Pol1=flip(a);
u=input('Enter the first estimate ');
v=input('Enter the second estimate ');
w=input('Enter the third estimate ');
z=input('Enter number of iterations ');
for n=1:z
delta0=(polyval(Pol1, v)-polyval(Pol1, u))/(v-u);
delta1=(polyval(Pol1, w)-polyval(Pol1, v))/(w-v);
h0=v-u;
h1=w-v;
a=(delta1-delta0)/(h1+h0);
b=a*h1+delta1;
c=polyval(Pol1,w);
g1=-2*c/(b+sqrt(b^2-4*a*c));
g2=-2*c/(b-sqrt(b^2-4*a*c));
if b+sqrt(b^2-4*a*c)>b-sqrt(b^2-4*a*c)
d=g1;
end
if b+sqrt(b^2-4*a*c)<b-sqrt(b^2-4*a*c)
d=g2;
end
x(n)=w+d;
u=v;
v=w;
w=x(n);
end
When I run it, MATLAB returns 'Undefined function or variable 'd'. d is calculated to be a complex number. MATLAB returns d when I run
or
separately, but does not do for the code. Why is that so?
or
separately, but does not do for the code. Why is that so?0 件のコメント
採用された回答
Walter Roberson
2020 年 12 月 31 日
if b+sqrt(b^2-4*a*c)>b-sqrt(b^2-4*a*c)
d=g1;
end
if b+sqrt(b^2-4*a*c)<b-sqrt(b^2-4*a*c)
d=g2;
end
That code will not assign d under a few circumstances:
Note:
b+sqrt(b^2-4*a*c)<b-sqrt(b^2-4*a*c) implies b + sqrt(b^2-4*a*c) - b < b - sqrt(b^2-4*a*c) - b implies sqrt(b^2-4*a*c) < - sqrt(b^2-4*a*c) implies 2*sqrt(b^2-4*a*c) < 0 implies sqrt(b^2-4*a*c) < 0 . However, algebraically, sqrt() is defined as "principle square root", which is positive when the value is positive, and is 1i * sqrt(-(b^2-4*a*c)) when b^2-4*a*c < 0 -- so sqrt(b^2-4*a*c) < 0 cannot happen unless you define an ordering of imaginary values with respect to 0. The MATLAB < operator ignores the imaginary component... but then you would be comparing 0 to 0, which would not be < .
Which is to say that your second test can never succeed, and your first test is always true unless b^2-4*a*c == 0 (a ligitimate test) or b^2-4*a*c < 0 (because the imaginary component is ignored)
その他の回答 (0 件)
参考
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!