Skip instance of a loop with error

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Abinav
Abinav 2020 年 12 月 29 日
コメント済み: Abinav 2020 年 12 月 29 日
Hi,
I am using nested loop to generate a range of variables and solve an equation.
for x = 1:1:20
for y = 1:1:20
for z = 1:1:20
fn = x+y+z; %The function is just a representation. I am actually performing a Finite Element Analaysis
ans = func(fn); %The equation is solved using an external function
end
end
end
The combination of variables (x,y,z) do not always form the root of the equation. When no solution is found, the Matlab function throws an error and exits the loop. However, I want the loop to continue and proceed checking the rest of the variable combinations. Is there a way to flag this error and continue through the looping process?
Thanks,
Abinav

採用された回答

James Tursa
James Tursa 2020 年 12 月 29 日
Something like this:
try
fn = x+y+z; %The function is just a representation. I am actually performing a Finite Element Analaysis
ans = func(fn); %The equation is solved using an external function
catch
continue
end
  1 件のコメント
Abinav
Abinav 2020 年 12 月 29 日
Thanks. It worked. I was stuck with this for days.

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その他の回答 (1 件)

Walter Roberson
Walter Roberson 2020 年 12 月 29 日
If func() is creating an error then use try/catch around the call to func()
  1 件のコメント
Abinav
Abinav 2020 年 12 月 29 日
Thanks. try/catch worked.

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