To find intersection point of two lines?
2 ビュー (過去 30 日間)
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x1=7.8;
x2=8.5;
y1=0.96;
y2=0.94;
p1 = polyfit([x1 x2], [y1 y2], 2);
b1= polyval(p1,1);
m1=polyval(p1,2)-b1;
x3=8.25;
x4=8.25;
y3=0;
y4=.99;
p2 = polyfit([x3 x4], [y3 y4], 2);
b2 = polyval(p2, 1);
m2 = polyval(p2, 2) - b2;
I got x value = -1.2867; from which co-ordinate this value corresponds to? Actually I want to compute intersection of two line with respect to x=[7.8 8.25 8.5]; y=[0.96 0.99 0.94]; over which those two lines are plotted?
x=[7.8 8.25 8.5];
y=[0.96 0.99 0.94];
p=polyfit(x,y,2);
f=polyval(p,x);
plot(x,y,'o',x,f,'-');
hold on;
line([7.8 8.5],[0.96 0.94]);
hold on;
line([8.25 8.25],[0 0.99]);
2 件のコメント
Image Analyst
2013 年 4 月 7 日
編集済み: Image Analyst
2013 年 4 月 7 日
Do you want to do it numerically (using quantized arrays), or analytically (using algebraic equations)? Why did you tag this as digital image processing?
採用された回答
Jing
2013 年 4 月 27 日
'polyxpoly' can get intersect points for lines. Is this what you want?
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