PolarAxes in Matlab App Designer

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Taha Adel
Taha Adel 2020 年 12 月 26 日
コメント済み: Steven Lord 2020 年 12 月 27 日
Hello,
Simply, I need a way to define a PolarAxes object under parent object in Matlab App Designer. I tried the following code, but it doesn't work.!
pax = polaraxes(app.parent)
Hint: I took a look at the example of plotting polar plot in App Designer in the documentation, but I don't know where to find the actual code.

採用された回答

Steven Lord
Steven Lord 2020 年 12 月 26 日
From the Release Notes it appears support for polaraxes in App Designer apps was added in release R2018b.
  2 件のコメント
Taha Adel
Taha Adel 2020 年 12 月 26 日
Is there a way to update my version to 2018b by downloading the comulitive update files?
Steven Lord
Steven Lord 2020 年 12 月 27 日
No, there is no "install this collection of files to upgrade release X to release X+1" package. Each general release is independent of previous releases. [For recent releases, there are update releases but those apply bug fixes to a specific release, like release R2020a to R2020a Update 1.]
Depending on your license and your maintenance you may be able to download and install release R2018b or a later release.

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その他の回答 (2 件)

Mario Malic
Mario Malic 2020 年 12 月 26 日
Example taken from this website
theta = 0:0.01:2*pi;
rho = sin(2*theta).*cos(2*theta);
pax = polaraxes(app.Panel);
polarplot(pax,theta,rho)
  6 件のコメント
Taha Adel
Taha Adel 2020 年 12 月 26 日
編集済み: Taha Adel 2020 年 12 月 26 日
Unfortunately, I couldn't find any demos related to polar plot in the software :( and the PolarAxes function still doesn't work by any means.
Mario Malic
Mario Malic 2020 年 12 月 26 日
So I guess polar axes are not supported in 2018a.

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Taha Adel
Taha Adel 2020 年 12 月 26 日
Any ideas?

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