フィルターのクリア

Confused about function solve

1 回表示 (過去 30 日間)
yuquan xiao
yuquan xiao 2020 年 12 月 24 日
コメント済み: yuquan xiao 2020 年 12 月 29 日
I am trying to use the function "solve" to find out the solution of inequality specified in cond1. Cond1 is shown in the following picture:
However, the solution is not obtained. I also plot the function given by the left of "cond1". Corresponding result shows there exactly exists the feasible solution.
Help!
Thank you in advance!
syms x;
cond1 = (x - 7) * x^2 / 2 - (4 + x)*2 >= 0;
sol = solve(cond1, x, 'ReturnConditions', true);
sol.conditions
  2 件のコメント
Walter Roberson
Walter Roberson 2020 年 12 月 24 日
Convert it to an equality and solve(), and throw away any complex-valued roots. Then for each root, check to see which side of the root the inequality holds on.
Rik
Rik 2020 年 12 月 24 日
Comment posted as flag by yuquan xiao:
Thank you! But I still do not know why such an inequality can not be directly solved with solve().

サインインしてコメントする。

採用された回答

Milan Padhiyar
Milan Padhiyar 2020 年 12 月 28 日
Hello Yuquan,
When you are trying to find the root of an inequality equation using the ‘solve’ function, sometimes it is required to give assumptions for the variable to get an explicit solution.
For example, in your query, if we assume that ‘x’ is greater than zero then we can get an explicit solution.
Please find here the modified code:
syms x;
assume(x > 0);
cond1 = (x - 7) * x^2 / 2 - (4 + x)*2 >= 0;
sol = solve(cond1, x, 'ReturnConditions', true);
sol.conditions
Please refer to the below link for example on finding roots of an inequality equation.
Thank You!
  1 件のコメント
yuquan xiao
yuquan xiao 2020 年 12 月 29 日
Thank you very much! It works!

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeEquation Solving についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by