Mixed Integer Linear Programming Problem
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I am trying to solve a integer linear programming problem, written in matlab as follows:
fs = 170;
Ts = 1/fs;
t = 0:Ts:1;
fo = 20;
f = -1*ones(1,171);
intcon = 1:length(f); %% All variables are integers.
lb = zeros(length(171),1); %%
ub = 1*ones(length(171),1); %% Enforces the optimization variables are binary.
Aeq = [];
beq = [];
A = ADS; %% Teoplitz Matrix (Convolution to Matrix Multiplication)
b = 5.*sin(2*pi*fo*t); %%
x = intlinprog(f,intcon,A,b,Aeq,beq,lb,ub);
When I try to solve this in matlab using default options, it tells me that no feasible solution exists. Then I removed the integer constraints and tried resolving it using linprog solver. It again tells me the same thing. I do not see any reason why this should happen.
I was just wondering if the reason for this might be the linear constraint b which is a sinusoidal? When I put b as a constant value, it solves the optimization problem.
Can someone please give me a bit more insight as to the reason of infeasibility in this case?
4 件のコメント
Walter Roberson
2020 年 12 月 23 日
What are the mininum and maximum number of positive and negative entries in one row of the toeplitz matrix?
For example if all of the entries except for (say) 3 were negative, and the rest positive, then with your f being all negative 1, that could turn into a sum that could not feasibly be negative enough to satisfy the 5*sin() being as low as -5
回答 (2 件)
Matt J
2020 年 12 月 24 日
編集済み: Matt J
2020 年 12 月 24 日
Since your unknown x(i) are bounded between 0 and 1, an upper bound on abs(A*x) is sum(abs(A),2). It seems doubtful to me that sum(abs(A),2) for the matrix you've shown could ever exceed 5. Therefore A*x could never reach a value less than -5, which it would have to in order for A*x to be bounded from above by b=5.*sin(2*pi*fo*t).
0 件のコメント
Alan Weiss
2020 年 12 月 27 日
You might find the following documentation useful:
Alan Weiss
MATLAB mathematical toolbox documentation
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