I´m trying to plot this function, which is an analytical solution of a partial equation, the equiation is below. This is my scipt. I don´t why that error is still apearing.
%Data
L=1; %m
p=1; %kg/m^3
G=0.1; %kg/ms
u=0.1; %m/s
%Boundary Conditions
po=1;
pL=0;
x=0:0.1:L;
p_a=((exp.((p*u)/G.*x)-1)./(exp(p*u*L/G)-1).*(pL-po))+po;
plot(x,p_a)
I get this error:
>> p_a=((exp.((p*u)/G.*x)-1)./(exp(p*u*L/G)-1).*(pB-pA))+pA;
Matrix dimensions must agree.

 採用された回答

KSSV
KSSV 2020 年 12 月 15 日

2 投票

It should be exp() not exp.()..there is a typo error.
%Data
L=1; %m
p=1; %kg/m^3
G=0.1; %kg/ms
u=0.1; %m/s
%Boundary Conditions
po=1;
pL=0;
x=0:0.1:L;
p_a=((exp((p*u)/G.*x)-1)./(exp(p*u*L/G)-1).*(pL-po))+po; % <---- changed here in first exp
plot(x,p_a)

3 件のコメント

Guillermo Nuñez
Guillermo Nuñez 2020 年 12 月 15 日
Hi! Thanks for your answer, there´s still the same error. Any other idea?
KSSV
KSSV 2020 年 12 月 16 日
There is no error......see the attched plot. Showus the code which you tried which lead to error.
Guillermo Nuñez
Guillermo Nuñez 2020 年 12 月 16 日
You´re right man! I was solving in the same code the equation by a numerical way and declared the numerical vector solution as "p", same variable name as the density. Sorry I didn´t checked it before. Thank you so much bro.

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

ヘルプ センター および File Exchange2-D and 3-D Plots についてさらに検索

製品

リリース

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by