for loop to create array
古いコメントを表示
I am trying to create three arrays of concentration. Each array uses some of the same constants, however different calues for Kd and Ji.
The only variable changing in the equation to create a array is time (1 to 300 years).
Any help would be great:
%Given through all
JN = (60 * 10^15)/ 2.12;
Co = 415;
e = 2.71828182845;
V = 4 *10^21;
%Ji and Kd for each part 1,2,3
%1
Ji1=(9.1*10^15)/2.12;
KD1 = (2.5 * 10^-2);
%2
Ji2=(9.1*10^15)/2.12;
KD2 = (1.8 * 10^-2);
%3
Ji3=(14*10^15)/2.12;
KD3 = (2 * 10^-2);
%create arrays
t=1:300;
C1=[];
C2=[];
C3=[];
%Calculation of each part using equation given
for i = 1:300
C1= ((JN + Ji1)/(KD1 * V))+(Co - ((JN + Ji1)/(KD1 * V)))*e^(-KD1*t(i));
end
for i = 1:300
C2= ((JN + Ji2)/(KD2 * V))+(Co - ((JN + Ji2)/(KD2 * V)))*e^(-KD2*t(i));
end
for i = 1:300
C3= ((JN + Ji3)/(KD3 * V))+(Co - ((JN + Ji3)/(KD3 * V)))*e^(-KD3 * t(i));
end
回答 (1 件)
Walter Roberson
2020 年 12 月 7 日
No loops
C1= ((JN + Ji1)/(KD1 * V))+(Co - ((JN + Ji1)/(KD1 * V)))*exp(-KD1*t);
Notice exp() and notice t is not subscripted
カテゴリ
ヘルプ センター および File Exchange で Loops and Conditional Statements についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!