Inserting a function in a matrix.
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Jason Psimopoulos
2020 年 12 月 7 日
編集済み: Jason Psimopoulos
2020 年 12 月 9 日
I am trying to solve the system above.I think I got right the first part of the quation with a for loop(code bellow) L = 51;
ws1 = 0.4*pi;
wp1 = 0.5*pi;
Ks1 = 1;
Kp = 2;
wo = (ws1+wp1)/2;
G = 1000;
w = [0:(G)]*pi/G;
W = Ks1*(w<=ws1) + Kp*(w>=wp1)
D = (wo>=w);
N=(L-1)/2
m=0:N
k=1:1001
for i = 0:N
F(i+1,:)=sum(arrayfun(@(k) (W(k).^2).*D(k).*cos(w(k).*i), 1:1000))
end
I am struggling though in the second part.My code looks like this but it does not seem to work.
for i = 0:N
for p = 0:N
F2=@(k)(W(k).^2).*D(k).*(cos(w(k).*i).*(cos(w(k).*p))')
end M[i+1,p+1]=sum[arrayfun(@(k) F2(k), 1:1000)]
end
Does anyone know how I could possibly fix that.I also download the symbolic math toolbox but I was not able to find something to help me with that.
2 件のコメント
Théophane Dimier
2020 年 12 月 8 日
編集済み: Théophane Dimier
2020 年 12 月 8 日
Hi,
that line looks a bit weird:
end M[i+1,p+1]=sum[arrayfun(@(k) F2(k), 1:1000)]
What do you want to do there? you should not have a statement after the end. Also, functions are called with parenthese () and not brackets []. To index arrays one should also use parentheses () and not brackets [] (unlike python or C)
Considering that it was a typo, would the following work?
M(i+1,p+1)=sum(arrayfun(@(k) F2(k), 1:1000))
end
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