Solving system of equations

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Rasto
Rasto 2013 年 3 月 24 日
Hello,
How to solve this task, where to calculate xE1, xE2, yE1, yE2?
Thanks in advance for any advice.
clear all; clc; close all;
CE=5; xC=1; yC=2; xD=3; yD=4;
eqnE1='CE^2=(xC-xEsol)^2+(yEsol-yC)^2';
eqnE2='(yEsol-yC)/(xC-xEsol)=(yC-yD)/(xD-xC)';
solE=solve(eqnE1, eqnE2, 'xEsol, yEsol');
xxE=eval(solE.xEsol);
yyE=eval(solE.yEsol);
xE1=xxE(1);
xE2=xxE(2);
yE1=yyE(1);
yE2=yyE(2);

採用された回答

Walter Roberson
Walter Roberson 2013 年 3 月 24 日
When you use
eqnE1='CE^2=(xC-xEsol)^2+(yEsol-yC)^2';
then you are creating a string. The existing values CE and so on are not going to be substituted into that string.
You should not eval() a symbolic result, as symbolic results are not in MATLAB syntax. If you want to import values from the workspace (such as CE) then you should use subs(), possibly followed by double().
  2 件のコメント
Rasto
Rasto 2013 年 3 月 24 日
Thank you for your answer, but I do not know how to think. Can I please give you the example?
Walter Roberson
Walter Roberson 2013 年 3 月 24 日
solE=solve(subs(eqnE1), subs(eqnE2), 'xEsol, yEsol');
xxE = double(solE.xEsol);

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