How to plot the opposite direction field
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I have this code written for the flow field. But I want the opposite to happen, the image below should be inside out. The longest direction lines should be on the inside and the outside should have the smallest direction lines. It should be inside out, if that makes sense
%Define parameters for the velocity profile
w=2*pi; %rad/s
R=15; %cm
%Create a meshgrid of cylindrical coordinates
[r,theta]=meshgrid(R:R/10:0,2*pi:pi/12:0);
%Define the Cartesian coordinates
x=r.*cos(theta);
y=r.*sin(theta);
%Calculate the linear velocity components in cartesian coordinates
u=-w.*r.*sin(theta);
v=w.*r.*cos(theta);
%Create a 2d vector plot of the velocity
quiver(x,y,u,v);
daspect([1 1 1]);
xlabel('x, cm');
ylabel('y, cm');
title('Title')
%Define the axis ranges
axis([-R R -R R]);
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採用された回答
Ameer Hamza
2020 年 12 月 7 日
Try this
quiver(x, y, 1./u, 1./v);
2 件のコメント
Ameer Hamza
2020 年 12 月 7 日
編集済み: Ameer Hamza
2020 年 12 月 7 日
The suggestion about meshgrid was given by VBBV. I only suggested to modify quiver() line. Anyway, try the following code
%Define parameters for the velocity profile
w=2*pi; %rad/s
R=15; %cm
%Create a meshgrid of cylindrical coordinates
[r,theta]=meshgrid(R/10:R/10:R,0:pi/10:2*pi);
%Define the Cartesian coordinates
x=r.*cos(theta);
y=r.*sin(theta);
%Calculate the linear velocity components in cartesian coordinates
u=-w.*1./r.^(1/2).*sin(theta);
v=w.*1./r.^(1/2).*cos(theta);
%Create a 2d vector plot of the velocity
quiver(x,y,u,v);
daspect([1 1 1]);
xlabel('x, cm');
ylabel('y, cm');
title('Title')
%Define the axis ranges
axis([-R R -R R]);
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