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Increasing value of filter till required number of solutions each reached
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I need a while loop to increase the length, n, of a filter until I have 8 values that satisfy a result. The code that I have does not seem to work.
index = [];
while length(index)>8
n = 1;
filtered_ipam_relative_hand_position = moving_average_filter(ipam_relative_hand_position, n);
velocity=zeros(size(filtered_ipam_relative_hand_position));
for i=1:length(data)
for j= 1:3
x = i-1;
y = i+1;
if x == 0
x = 1;
else
if i == length(data)
y = length(data);
end
end
velocity(i,j) = (filtered_ipam_relative_hand_position(y,j)- filtered_ipam_relative_hand_position(x,j))/0.08;
end
end
magnitude_velocity = zeros(length(velocity),1);
for i=1:length(data)
magnitude_velocity(i)=((velocity(i,1))^2 + (velocity(i,2))^2 + (velocity(i,3))^2)^0.5;
end
for i=1:length(data)-1
if (magnitude_velocity(i+1,1)<0.01) && (magnitude_velocity(i,1)>0.01)
index = [index i];
end
end
n=n+1;
end
0 件のコメント
回答 (1 件)
Walter Roberson
2013 年 3 月 22 日
length([]) is 0, which is <= 8, so your "while" loop never executes.
2 件のコメント
Walter Roberson
2013 年 3 月 26 日
The problem is not your definition of "index", the problem is your "while" condition.
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