How to get distance & angle of a point from the center of a minor axis ??

2 ビュー (過去 30 日間)
Haytham Mohamed
Haytham Mohamed 2013 年 3 月 20 日
I want to calculate the distance & angle of a point like The point in the below Image : P.S the Center Point isn't (0,0)

採用された回答

Matt Tearle
Matt Tearle 2013 年 3 月 20 日
編集済み: Matt Tearle 2013 年 3 月 21 日
Do you have the coordinates of the point and the center (in standard Cartesian coordinates)? If so, just use norm and atan2 of the difference between the two:
p1 = rand(2,1)
p2 = rand(2,1)
d = p2 - p1
norm(d)
atan2(d(2),d(1))
EDIT TO ADD (In response to your comment): Still the same idea -- atan(delta_y,delta_x). It seems that you have data in the form of whole vectors of (x,y) points, and a single center point, in which case:
% coordinates of points
X = [1;2;3;4];
Y = [9;8;7;6];
% coordinates of center
X0 = 2;
Y0 = 2;
% take the difference
dX = X - X0;
dY = Y - Y0;
% and calculate the length
sqrt(dX.^2 + dY.^2)
% and angle
atan2(dY,dX)
% or atan2d(dY,dX) if you prefer degrees to radians
% visualize, for sanity
plot(X,Y,'o',X0,Y0,'x')
  1 件のコメント
Haytham Mohamed
Haytham Mohamed 2013 年 3 月 21 日
sorry bro , but i don't understand how to get the angle . let me give u some input :
X =[1;2;3;4]
Y =[9;8;7;6]
Center Is (2,2)
How to get the angle of each point from center

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeInteractions, Camera Views, and Lighting についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by