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Connecting like numbers in a matrix

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Harold
Harold 2013 年 3 月 15 日
Suppose I have a matrix of the following data:
data = [6, 5, 3, 0, 0, 1; ...
0, 0, 0, 0, 0, 2; ...
0, 0, 0, 0, 0, 4; ...
0, 0, 0, 0, 0, 0; ...
6, 0, 0, 0, 0, 0; ...
5, 0, 4, 0, 0, 0]
What I would like to do is find the like entries that I can connect directly to by remaining on the edges of the matrix. So for instance, after applying this function I should get
newdata = [6, 5, 3, 0, 0, 1; ...
6, 0, 0, 0, 0, 2; ...
6, 0, 0, 0, 0, 4; ...
6, 0, 0, 0, 0, 4; ...
6, 0, 0, 0, 0, 4; ...
5, 0, 4, 4, 4, 4]
  2 件のコメント
Cedric
Cedric 2013 年 3 月 15 日
編集済み: Cedric 2013 年 3 月 15 日
Look at what you get when you run the following:
for ii = 1 : size(data,1)
data(ii, end)
end
now you could exploit this approach to follow "edges" of your matrix and maybe update its elements.
Harold
Harold 2013 年 3 月 15 日
Ok, I will try this out. I will have to think about the structure some more since I will have to start at some nonzero value on an edge and work my way around until I reach another entry with the same value, whilst making sure any values I "pass" through are zero.

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