How can I solve an equation with more than one variable?

1 回表示 (過去 30 日間)
Aybike Elverdi
Aybike Elverdi 2020 年 12 月 1 日
コメント済み: Aybike Elverdi 2020 年 12 月 1 日
Hi,
I have constants which are
G=44*10^3;
b=2.95e-10;
tao=0.02;
k=1.38e-23;
delta_fo=0.5;
epsilon_ref=10^6;
q=1.8;
p=0.3;
And also I have these variables
epsilon_p=[0.001,0.01,0.1,1,10]
T=[773,873,973,1073,1173]
My equation is
sigma_t=tao*G*(1-(((k*T)/(delta_fo*G*b^3*log(epsilon_ref/epsilon_p)))^(1/q))^(1/p))
I want to solve this equation for example epsilon_p=0.001 when T=773.
But can't do anything.Hope anyone can help me.

採用された回答

Stephan
Stephan 2020 年 12 月 1 日
編集済み: Stephan 2020 年 12 月 1 日
You can solve for all cases in one calculation and save teh result as a matrix by using a function handle:
G=44*10^3;
b=2.95e-10;
tao=0.02;
k=1.38e-23;
delta_fo=0.5;
epsilon_ref=10^6;
q=1.8;
p=0.3;
epsilon_p=[0.001,0.01,0.1,1,10]
T=[773,873,973,1073,1173]
sigma_t= @(epsilon_p,T) tao*G*(1-(((k*T')./(delta_fo*G*b^3*log(epsilon_ref./epsilon_p))).^(1/q)).^(1/p))
sol = sigma_t(epsilon_p,T)
result:
sol =
1.0e+09 *
-0.2663 -0.3313 -0.4242 -0.5643 -0.7910
-0.3336 -0.4150 -0.5314 -0.7069 -0.9908
-0.4078 -0.5072 -0.6495 -0.8641 -1.2112
-0.4888 -0.6080 -0.7786 -1.0358 -1.4518
-0.5765 -0.7171 -0.9182 -1.2216 -1.7122
This works because of vectorization - on of the things that make Matlab great. Every row is one value of T and all the values of epsilon. Every column stands for changing T and the correspondig entry in epsilon:
>> Line3 = sigma_t(epsilon_p,T(3))
Line3 =
1.0e+09 *
-0.4078 -0.5072 -0.6495 -0.8641 -1.2112

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeMathematics についてさらに検索

製品


リリース

R2019b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by