User defined FFT function parameter not recognized
6 ビュー (過去 30 日間)
I am trying to use the FFT function explained in this link
but when I use a nx2 signal and a scalar value for ScanRate I get an error :
Shall someone tell why isnt the function getting my input value
Unrecognized function or variable 'ScanRate'.
% function [frq, amp, phase] = simpleFFT( signal, ScanRate)
% Purpose: perform an FFT of a real-valued input signal, and generate the single-sided
% output, in amplitude and phase, scaled to the same units as the input.
% signal: the signal to transform
% ScanRate: the sampling frequency (in Hertz)
% frq: a vector of frequency points (in Hertz)
% amp: a vector of amplitudes (same units as the input signal)
% phase: a vector of phases (in radians)
function [frq, amp, phase] = simpleFFT( signal, ScanRate)
n = length(signal);
z = fft(signal, n); %do the actual work
%generate the vector of frequencies
halfn = floor(n / 2)+1;
deltaf = 1 / ( n / ScanRate);
frq = (0:(halfn-1)) * deltaf;
% convert from 2 sided spectrum to 1 sided
%(assuming that the input is a real signal)
amp(1) = abs(z(1)) ./ (n);
amp(2:(halfn-1)) = abs(z(2:(halfn-1))) ./ (n / 2);
amp(halfn) = abs(z(halfn)) ./ (n);
phase = angle(z(1:halfn));
回答 (1 件)
John D'Errico 2020 年 11 月 29 日
編集済み: John D'Errico 2020 年 11 月 29 日
How did you call the function? When you get an error, report the ENTIRE error message, everyting in red. This lets us know how you called the function.
Just because you have a variable named ScanRate in your workspace does not tell MATLAB to automatically pass it into your function.
If you want the function to see the variable, then you NEED to pass it in. Call it like this:
[frq, amp, phase] = simpleFFT( signal, ScanRate);
So you need ot pass in TWO arguments to your function. They can have any names as you pass them in, but inside the function, now ScanRate will be defined.
If you don't, well, then MATLAB will generate an error - the one you got.