Having problems displaying the real and imaginary parts of a complex root

5 ビュー (過去 30 日間)
Suman Koirala
Suman Koirala 2013 年 3 月 12 日
This is what I have. It works all fine in identifying the root but doesn't do anything with displaying the real and complex roots although I think I have it.
a=input('Enter a: ');
b=input('Enter b: ');
c=input('Enter c: ');
d=(b^2)- 4*a*c;
if d>0
disp('This equation had two real roots');
r1= (-b+sqrt(d))/(2*a)
r2= (-b - sqrt(d))/(2*a)
elseif d==0
disp('This equation has one real root');
r1= (-b+sqrt(d))/(2*a)
else
disp('This equation has two imaginary roots');
r1= (-b+sqrt(d))/(2*a)
r2= (-b - sqrt(d))/(2*a)
real(r1)
real(r2)
y1=imag(r1)
y2=imag(r2)
end

採用された回答

Youssef  Khmou
Youssef Khmou 2013 年 3 月 12 日
hi, what is the problem exactly !
delete the part :
real(r1);real(r2);
y1=imag(r1);y2=imag(r2);
I think the code is fine :
Enter a: 2
Enter b: 2
Enter c: 2
This equation has two imaginary roots
r1 =
-0.5000 + 0.8660i
r2 =
-0.5000 - 0.8660i

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeLogical についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by