Question about constraints in optimization problems
1 回表示 (過去 30 日間)
古いコメントを表示
I have the following victor:
A=[ 0.1 0.1 0.3 0.2 0.3]
The sum of this vector is 1, but when I try the following code:
Test = (sum(A(:)) ==1)
If ( Test == 1 )
"True"
Else
"False"
The results is always FALSE.
What is the problem
0 件のコメント
回答 (1 件)
Ameer Hamza
2020 年 11 月 29 日
編集済み: Ameer Hamza
2020 年 11 月 29 日
This is due to the finite precision of floating-point numbers. Calculations on floating points numbers can accumulate errors, so the value is not exactly equal to one. You need to allow a bit of tolerance in comparing floating-point values. For example
Test = (sum(A(:)) ==1)
if ( abs(Test-1) < 1e-6 )
"True"
else
"False"
end
3 件のコメント
参考
カテゴリ
Help Center および File Exchange で Quadratic Programming and Cone Programming についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!