Smoothing the plots with points

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Doyeon Kim
Doyeon Kim 2020 年 11 月 28 日
コメント済み: KSSV 2020 年 11 月 28 日
x1 = [0.05, 0.101, 0.201, 0.401, 0.797, 1.597, 3.196, 6.39, 10.01];
y1 = [0.053, 0.832, 2.744, 3.737, 3.775, 3.823, 3.9, 4.039, 4.207];
x2 = [0.049, 0.097, 0.2, 0.403, 0.739, 1.596, 3.201, 6.39, 10];
y2 = [0.113, 0.797, 6.096, 7.271, 7.426, 7.603, 7.894, 8.266, 8.666];
x3 = [0.05, 0.099, 0.201, 0.402, 0.804, 1.6, 3.219, 6.38, 10];
y3 = [0.25, 1.595, 7.889, 11.403, 12.502, 12.7, 13.54, 14.672, 15.6];
How to smooth those? Also, I want to limit the x axis from 0 to 10.
  1 件のコメント
KSSV
KSSV 2020 年 11 月 28 日
Have a look on interp1

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回答 (1 件)

KSSV
KSSV 2020 年 11 月 28 日
Try fitting a Bezier Curve: I have referred this link: https://in.mathworks.com/matlabcentral/fileexchange/33828-generalised-bezier-curve-matlab-code . Please note that code can be optimized.
x1 = [0.05, 0.101, 0.201, 0.401, 0.797, 1.597, 3.196, 6.39, 10.01];
y1 = [0.053, 0.832, 2.744, 3.737, 3.775, 3.823, 3.9, 4.039, 4.207];
% From here take from the link
p = [x1' y1'] ;
n = size(p,1) ;
n1 = n-1 ;
sigma = zeros(1,n1+1) ;
for i=0:1:n1
sigma(i+1)=factorial(n1)/(factorial(i)*factorial(n1-i)); % for calculating (x!/(y!(x-y)!)) values
end
l=[];
UB=[];
for u=0:0.002:1
for d=1:n
UB(d)=sigma(d)*((1-u)^(n-d))*(u^(d-1));
end
l=cat(1,l,UB); %catenation
end
P=l*p;
figure
hold on
plot(p(:,1),p(:,2),'b')
plot(P(:,1),P(:,2),'r')
legend("Original","BeizerCurve")
  2 件のコメント
Doyeon Kim
Doyeon Kim 2020 年 11 月 28 日
Thanks a lot!
KSSV
KSSV 2020 年 11 月 28 日
Thanks is accepting/voting the answer.

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