How to understand the symbolic inverse fourier transform result?

1 回表示 (過去 30 日間)
FastCar
FastCar 2020 年 11 月 22 日
コメント済み: FastCar 2022 年 6 月 17 日
Dear all,
I need to perform a symbolic inverse fourier transformate. I tried the following
syms alpha lambda n positive %alpha, lambda and n are real positive variables
syms w vc real %w and vc are real variables
PSD = (alpha/(alpha+1)*dirac(w)+1/(alpha+1)*n*sin(pi/n)/(2*pi*vc)*1/(1+(abs(w)/vc)^n))
ifourier(PSD)
and I got as result
(alpha/(alpha + 1) + (n*sin(pi/n)*(fourier(heaviside(w)/((w/vc)^n + 1), w, -x) + fourier(heaviside(-w)/((-w/vc)^n + 1), w, -x)))/(2*vc*pi*(alpha + 1)))/(2*pi)
but I am not able to understand the part
fourier(heaviside(w)/((w/vc)^n + 1), w, -x)
what does it mean?
Many thanks

回答 (1 件)

Swetha Polemoni
Swetha Polemoni 2020 年 11 月 29 日
Hi Fast Car,
This issue of working with ifourier has been brought to the notice of developers. They may investigate the matter further.
  2 件のコメント
FastCar
FastCar 2020 年 11 月 29 日
Ok, many thanks. I do not know why your previous answer and my comment are not visible anymore. If you can, please keep me posted.
Many thanks
Fast car
FastCar
FastCar 2022 年 6 月 17 日
Any update?

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeCalculus についてさらに検索

製品


リリース

R2018b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by