how to divide two structures?
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A is a structure. B is a structure. i need to perform A/B. How to get it?
1 件のコメント
Jan
2013 年 3 月 4 日
Currently we can only guess, what the "/" operator should do for your data. Does "structure" mean STRUCT arrays? Should something happen with the fields?
回答 (2 件)
Walter Roberson
2013 年 3 月 4 日
You do not. What would it even mean? What would you expect as the result of
struct('P', {5:10}, 'Q', {magic(17)}) / struct('S', {'hello'}, 'T', false(7,8), 'P', {2})
??
0 件のコメント
Azzi Abdelmalek
2013 年 3 月 4 日
A=struct('a1',num2cell(1:10))
B=struct('b1',num2cell(11:20))
C=cellfun(@(x,y) x/y,struct2cell(A),struct2cell(B),'un',0)
C=cell2struct(C,{'c1'},1)
0 件のコメント
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