color of marks in polar plot
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I want to make a polar plot. I have 16 pair of values and want to show them with markers as their colors changes gradually from pair 1 to pair 16. Could you please help me?
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Matt Fig
2011 年 4 月 30 日
Walter hit on the only solution that makes sense to me. It is not that bad, for instance:
% Sample Data...
A = linspace(0,2*pi,16);
B = A.^2;
mat = repmat((0:1/15:1).',1,3);
polar(A,B);hold on % If you want a connecting line.
for ii = 16:-1:1
L(ii) = polar(A(ii),B(ii),'o');
hold on
set(L(ii),'markerfacecolor',mat(ii,:),...
'markeredgecolor',mat(ii,:))
end
6 件のコメント
Matt Fig
2011 年 5 月 1 日
The dots are still there, but you wanted to go from black to white. Thus the final few are nearly white and don't show up well. To avoid this you could either change the axis color to introduce contrast, or change the range of the dots' color. For example:
mat = repmat((0:.7/15:.7).',1,3);
which would go from black to grey.
その他の回答 (1 件)
Walter Roberson
2011 年 4 月 30 日
polar() the entire vector first. Then "hold on" and iterate through the theta/rho pairs polar()'ing each pair individually with the marker and color that you want for that point.
5 件のコメント
Walter Roberson
2011 年 4 月 30 日
Well, you could interpolate (calculate) the colors you pass to polar() instead of using color letters.
You could polar() in the lines all at one time, and then you could convert the polar coordinates to cartesian and scatter() in the points, specifying a matrix of colors.
You could polar() in the lines all at one time, and then you could convert the polar coordinates to cartesian and then you could use patch() to draw very thin lines, and use vertex shading in the patch()
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