# How do I use function for a function which has a matrix with variable index?

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Fidele Adanvo 2020 年 11 月 17 日
コメント済み: Fidele Adanvo 2020 年 11 月 17 日
function[PacksA,PacksB,ContA,ContB,AR,BR,fA,fB]=OutAR_NotOutBR(i,Max,AR,BR,fB,fA,ContB)
if AR<Max
%PacksB, PacksA, ContB, ContA are a vector that varies according to the operation
PacksB=3; fB=fB+1;
PacksA=2; ContA(AR+1)=i; AR=AR+1;
if BR==1
PacksB(ContB(1))=4; fB=fB+1;
ContB(1)=0; BR=BR-1;
elseif BR>=2
PacksB(ContB(1,1:2))=4; fB=fB+2;
if BR==2
ContB=0;
else
ContB(1)=ContB(3); ContB(1,2:3)=0;
end
BR=BR-2;
end
elseif AR==Max
PacksA=3; fA=fA+1;
PacksB=3; fB=fB+1;
if BR>0
PacksB(ContB)=4; fB=fB+BR;
end
ContB=0;
BR=0;
end
%Hello, can you help me solve this error?
%Error in ==> OutAR_NotOutBR at 2
if AR<Max
{??? Output argument "PacksA" (and maybe others)
not assigned during call to

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### 回答 (1 件)

James Tursa 2020 年 11 月 17 日

You don't have a branch for the AR>Max case. If you hit that condition, the output variables will not be assigned. Also, ContA doesn't appear to be set in the AR==Max case.
You should check that in all of the possible paths through your code, all of the output variables get assigned to something.
##### 8 件のコメント表示非表示 7 件の古いコメント
Fidele Adanvo 2020 年 11 月 17 日
Por exemple: if i=5
function []=()
PackA(5)=7 it's an example.
As you can see, I don't need to go through all the PacksA elements.

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