How to find longest sequennce within a character array?

lets say Im given a random character array such as: 'aaabee' and i want to find the longest sequence of vowels. How would i go about doing this?
so far I have:
cArr = 'aaabee';
vow = ['a', 'e', 'i', 'o', 'u'];
ans = strfind(cArr, vow);
but this just returns: [ ]
anyhelp would be appreciated!

回答 (2 件)

Ameer Hamza
Ameer Hamza 2020 年 11 月 16 日
編集済み: Ameer Hamza 2020 年 11 月 16 日

1 投票

You can use regexp
cArr = 'xzyhd';
vow = '([aeiou]+)';
tkns = regexp(cArr, vow, 'tokens');
if isempty(tkns)
n = 0;
else
n = max(cellfun(@numel, [tkns{:}]));
end
Result
>> n
n =
5

3 件のコメント

Setsuna Yuuki.
Setsuna Yuuki. 2020 年 11 月 16 日
Awesome!
That Guy
That Guy 2020 年 11 月 16 日
編集済み: That Guy 2020 年 11 月 16 日
this works, i just need it to output zero when a string without vowels is entered such as 'xzyhd' or ' ' .
sorry im so helpless this is my first experince with coding:(
Ameer Hamza
Ameer Hamza 2020 年 11 月 16 日
I have updated the answer. Now it will output 0 for the mentioned cases.

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Setsuna Yuuki.
Setsuna Yuuki. 2020 年 11 月 16 日
編集済み: Setsuna Yuuki. 2020 年 11 月 16 日

0 投票

cArr = 'aaabee';
vow = ['a', 'e', 'i', 'o', 'u'];
for n=1:length(vow)
a = strfind(cArr, vow(n)); %search letter by letter
repeat{n} = a; %place in "cArr"
if (a ~= NaN)
long(n) = length(a); %number of repetitions
else
long(n) = 0;
end
end
t = table(vow',long')
Table:

4 件のコメント

That Guy
That Guy 2020 年 11 月 16 日
Thanks! any hints on how to modify what you have to not be as specific? I need it to find the longest sequence of any vowels ie: 'aaeeaprii' would return a max value of 5 within long(n), right now your code returns 3 instead?
That Guy
That Guy 2020 年 11 月 16 日
Any help?
Setsuna Yuuki.
Setsuna Yuuki. 2020 年 11 月 16 日
編集済み: Setsuna Yuuki. 2020 年 11 月 16 日
has been interesting this problem, i changed all code because I understood bad your problem.
clear large;
cArr = 'aaeeaaapriioaeaaa';
vow = ['a', 'e', 'i', 'o', 'u'];
var = 1;
for n=1:length(vow)
a = strfind(cArr, vow(n));
if(var == 1)
var(length(var):(length(var)+length(a))-1)=a;
else
var(length(var)+1:length(var)+length(a))=a;
end
end
var = sort(var); m = 0;
cont = 1;
for n = 1:length(var)-1
if(var(n) == (var(n+1)-1) && n ~= length(var)-1)
cont = cont +1;
elseif (var(n) ~= (var(n+1)-1))
m = m+1;
large(m) = cont;
cont = 1;
elseif(n == (length(var)-1))
cont = cont+1;
m = m+1;
large(m) = cont;
end
end
[longSeq, index] = max(large);
fprintf("The longest sequence is %i and is the sequence %i \n",longSeq, index);
I think I did this in C ++ jaja xd
Image Analyst
Image Analyst 2020 年 11 月 16 日
What's the use case for this quirky thing? Why do you need to do it? It's not your homework you're asking people to do for you, is it? What's the real world use for this?

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