Array Operation Easy Question about formula.
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Hello
Why this equation is possible to solve in the current matlab, despite the fact that a few years ago it was impossible ?
X = [ 1;2;3] Y = [ 4;5;6] X'.*Y.
MATLAB R202b
3 件のコメント
Stephen23
2020 年 11 月 15 日
Original question by Mateusz Zak:
Array Operation Easy Question about formula.
Hello
Why this equation is possible to solve in the current matlab, despite the fact that a few years ago it was impossible ?
X = [ 1;2;3] Y = [ 4;5;6] X'.*Y.
MATLAB R202b
Original comment by Mateusz Zak:
Sorry.
X = [ 1;2;3] Y = [ 4;5;6] X'.*Y
回答 (1 件)
Ameer Hamza
2020 年 11 月 15 日
編集済み: Ameer Hamza
2020 年 11 月 15 日
It was introduced in R2016b. Read all about it here: https://blogs.mathworks.com/loren/2016/10/24/matlab-arithmetic-expands-in-r2016b/. Previously such a thing was only possible through bsxfun().
1 件のコメント
Ameer Hamza
2020 年 11 月 15 日
Yes, MATLAB automatically expand both matrices to have equal size and then use element-wise operation. In your case X' is [1x3] and Y is [3x1]. MATLAB repeat elements of X' and Y to make them 3x3 matrices.
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