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how can i use Richardson extrapolation procedure (in explicit Euler method)

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suketu vaidya
suketu vaidya 2020 年 11 月 10 日
function suketu
%euler exlicit method
h = 1;
x = 0:h:3;
y1 = [0];
for i = 1:length(x)-1
x(i+1)=x(i)+h;
y1(i+1) =y1(i) + h * f1(x(i), y1(i));
end
function dy = f1(x,y1)
y0 = -1;
dx=0.01;
d = 50;
c1=(y0-(d^2/(d^2+1)));
dy=c1*exp(-dx)+d*(sin(x)/(d^2+1))+d^2*(cos(x)/d^2+1);
end

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