Averaging the selected vector ranges

1 回表示 (過去 30 日間)
Lev Mihailov
Lev Mihailov 2020 年 11 月 6 日
コメント済み: Mathieu NOE 2020 年 11 月 9 日
Hello! I need to average the values ​​of a vector over 25 values
fr = mean(reshape(VectorTime, 25, [])); %
Error using reshape
Product of known dimensions, 25, not divisible into total number of elements, 523.
Error in TimeAndWordNN (line 1234)
frr = mean(reshape(VectorTime, 25, []));
When I try to make such a variant, I get an error, please help
for i=1:25:length(VectorTime) && i<length(VectorTime)
frr=mean(VectorTime(i:i+1)) % i(1)=1 i(2)=26
end
% tried what i need to do through the loop but nothing worked

採用された回答

Mathieu NOE
Mathieu NOE 2020 年 11 月 6 日
hello
my 2 fold suggestion , first is new code according to your expected results , and second is based on sliding averaging - function is in attachement !
enjoy
samples = 1000;
VectorTime = 1 + sin(2*pi*(1:samples)/samples)+ 0.25*rand(1,samples);
buffer = 25; % nb of samples for averaging
% zero overlap mean averaging
for ci=1:floor(length(VectorTime)/ buffer)
start_index = 1+(ci-1)*buffer;
stop_index = min(start_index+ buffer,length(VectorTime));
time_index(ci) = round((start_index+stop_index)/2);
frr(ci) =mean(VectorTime(start_index:stop_index)) %
end
figure(1),
plot((1:samples),VectorTime,'b',time_index,frr,'or');
% sliding avg method
out = myslidingavg(VectorTime, buffer);
figure(2),
plot((1:samples),VectorTime,'b',(1:samples),out,'r');
  1 件のコメント
Mathieu NOE
Mathieu NOE 2020 年 11 月 9 日
hello
please use this version of slidingavg (if you are interested in)
I have found a bug in the previous release
all the best

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeSubplots についてさらに検索

製品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by