Indices of 2D array
2 ビュー (過去 30 日間)
表示 古いコメント
I have a 1D (very big one) array like below:
data =[ 2 5 0 15 12 7 4 8 19 14 20 25 18 13 40 ];
I want to make the lowest value to zero in every 3 element. I firstly reshaped it to be like:
reshaped_data =
2 15 4 14 18
5 12 8 20 13
0 7 19 25 40
And then sorted each column and now I have the indices of the sorted data as below.
sorted_data_index =
2 1 3 3 3
1 2 2 2 1
3 3 1 1 2
So, please let me know how can I use sorted_data_index as indices of reshaped_data to be able to make the lowest values zero?
I can do this within a for loop, but it would be very slow.
Thanks
0 件のコメント
採用された回答
Sindar
2020 年 11 月 5 日
data =[ 2 5 0 15 12 7 4 8 19 14 20 25 18 13 40 ];
reshaped_data = reshape(data,3,[]);
[~,idx]=sort(reshaped_data,1,'descend');
reshaped_data( sub2ind( size(reshaped_data), idx(3,:), 1:size(reshaped_data,2)) ) = 0
reshaped_data =
2 15 0 0 18
5 12 8 20 0
0 0 19 25 40
その他の回答 (1 件)
Luna
2020 年 11 月 5 日
try this:
data =[ 2 5 0 15 12 7 4 8 19 14 20 25 18 13 40 ];
reshaped_data = reshape(data,3,length(data)/3);
[min_vals,idx] = min(reshaped_data);
idx_increment = 0:3:length(data)-3;
element_number_in_matrix = idx + idx_increment;
reshaped_data(element_number_in_matrix) = 0;
new_data = reshape(reshaped_data,1,length(data));
参考
カテゴリ
Find more on Multidimensional Arrays in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!